What is the derivative of (18/(x^4)) ?

The derivative of (18/(x^4)) is -(72)/(x^5)

What is the first derivative of (18/(x^4)) ?

The first derivative of (18/(x^4)) is -(72)/(x^5)

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\frac{d}{d x} (\frac{18}{x ^{4}})

- \frac{72}{x ^{5}}

Solution steps

\frac{d}{d x} (\frac{18}{x ^{4}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 18 \frac{d}{d x} (\frac{1}{x ^{4}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 18 \frac{d}{d x} (x^{- 4})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 18 (- 4 x^{- 4 - 1})

Simplify

18 (- 4 x^{- 4 - 1}) : - \frac{72}{x ^{5}}

= - \frac{72}{x ^{5}}

\int \frac{1}{sec ^{2} ( u )} d u

\int_{0}^{4} ∣ 2 x - 3 ∣ d x

\frac{s}{s + \frac{1}{2}}

e^{- x}, 5

\int 1 + \frac{2}{y} d y

What is the derivative of (18/(x^4)) ?
The derivative of (18/(x^4)) is -(72)/(x^5)
What is the first derivative of (18/(x^4)) ?
The first derivative of (18/(x^4)) is -(72)/(x^5)