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Popular >

y^'+2y=xy^{-2}

Solution

y^{^{'}} + 2 y = x y^{- 2}

Solution

Solution steps

y^{'} (x) + 2 y = x y^{- 2}

Solve Bernoulli ODE:

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Frequently Asked Questions (FAQ)

What is the solution for y^'+2y=xy^{-2} ?
The solution for y^'+2y=xy^{-2} is y=\sqrt[3]{(6e^{6x}x-e^{6x}+c_{1})/(12e^{6x)}}