What is the integral of 6x^5-4x^2+7/3 ?

The integral of 6x^5-4x^2+7/3 is x^6-(4x^3)/3+7/3 x+C

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integral of 6x^5-4x^2+7/3

\int 6 x^{5} - 4 x^{2} + \frac{7}{3} d x

x^{6} - \frac{4 x ^{3}}{3} + \frac{7}{3} x + C

Solution steps

\int 6 x^{5} - 4 x^{2} + \frac{7}{3} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 6 x^{5} d x - \int 4 x^{2} d x + \int \frac{7}{3} d x

\int 6 x^{5} d x = x^{6}

\int 4 x^{2} d x = \frac{4 x ^{3}}{3}

\int \frac{7}{3} d x = \frac{7}{3} x

= x^{6} - \frac{4 x ^{3}}{3} + \frac{7}{3} x

Add a constant to the solution

= x^{6} - \frac{4 x ^{3}}{3} + \frac{7}{3} x + C

t \to 0 lim (f (t))

\frac{d}{d x} (\frac{2 x - 3}{x - 1})

x \to 0 lim (e^{- 2 f (x)})

\frac{\partial}{\partial x} (\frac{1}{1 - y})

t \to 0 lim (\frac{sin ( - 4 t )}{t})

What is the integral of 6x^5-4x^2+7/3 ?
The integral of 6x^5-4x^2+7/3 is x^6-(4x^3)/3+7/3 x+C