What is the derivative of 2/(x-4) ?

The derivative of 2/(x-4) is -2/((x-4)^2)

What is the first derivative of 2/(x-4) ?

The first derivative of 2/(x-4) is -2/((x-4)^2)

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\frac{d}{d x} (\frac{2}{x - 4})

- \frac{2}{( x - 4 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{2}{x - 4})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (\frac{1}{x - 4})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 2 \frac{d}{d x} ((x - 4)^{- 1})

Apply the chain rule:

- \frac{1}{( x - 4 ) ^{2}} \frac{d}{d x} (x - 4)

= - \frac{1}{( x - 4 ) ^{2}} \frac{d}{d x} (x - 4)

\frac{d}{d x} (x - 4) = 1

= 2 (- \frac{1}{( x - 4 ) ^{2}} \cdot 1)

Simplify

2 (- \frac{1}{( x - 4 ) ^{2}} \cdot 1) : - \frac{2}{( x - 4 ) ^{2}}

= - \frac{2}{( x - 4 ) ^{2}}

\int \frac{x}{4 x + 1} d x

(6 x y - 2 y^{2} + 1) d x + (3 x^{2} - 4 x y) d y = 0

\int \frac{5}{6 x + 5} d x

\frac{x}{7 x ^{2} + 1}

f (x) = e^{2 e^{x}}

What is the derivative of 2/(x-4) ?
The derivative of 2/(x-4) is -2/((x-4)^2)
What is the first derivative of 2/(x-4) ?
The first derivative of 2/(x-4) is -2/((x-4)^2)