What is the solution for y^{''}+11y^'+24y=0,y(0)=1,y^'(0)=0 ?

The solution for y^{''}+11y^'+24y=0,y(0)=1,y^'(0)=0 is y=(1+3/5)e^{-3t}-3/5 e^{-8t}

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y^{''}+11y^'+24y=0,y(0)=1,y^'(0)=0

y^{^{''}} + 11 y^{^{'}} + 24 y = 0, y (0) = 1, y^{^{'}} (0) = 0

y = (1 + \frac{3}{5}) e^{- 3 t} - \frac{3}{5} e^{- 8 t}

Solution steps

y^{''} (t) + 11 y^{'} (t) + 24 y = 0

Solve linear ODE:

y = (1 + \frac{3}{5}) e^{- 3 t} - \frac{3}{5} e^{- 8 t}

y = (1 + \frac{3}{5}) e^{- 3 t} - \frac{3}{5} e^{- 8 t}

t \to 0 lim (\frac{2}{t} - \frac{2}{e ^{t} - 1})

\frac{d}{d x} ((x^{8} - 1)^{3})

\int cot^{2} (x cs) c^{4} x d x

\frac{d}{d x} (- 2 (x + 3) (x - 3)^{2})

\frac{d}{d x} (\frac{cos ( y ) + 2 e ^{- x} cos ( x )}{y})

What is the solution for y^{''}+11y^'+24y=0,y(0)=1,y^'(0)=0 ?
The solution for y^{''}+11y^'+24y=0,y(0)=1,y^'(0)=0 is y=(1+3/5)e^{-3t}-3/5 e^{-8t}