What is the derivative of y=x^2+2 ?

The derivative of y=x^2+2 is 2x

What is the first derivative of y=x^2+2 ?

The first derivative of y=x^2+2 is 2x

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derivative of

y = x^{2} + 2

2 x

Solution steps

\frac{d}{d x} (x^{2} + 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (2)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (2) = 0

= 2 x + 0

Simplify

= 2 x

\frac{\partial}{\partial x} (4 y e^{4 x y})

\frac{d}{d x} (4 x - 8)

f (θ) = \frac{sec ( θ )}{1 + sec ( θ )}

f (x) = 4 x^{2} + 7 x

\int \frac{1}{u ^{2} - 4} d u