What is the solution for y^'cos(x)+ysin(x)=2cos^3(x)sin(x) ?

The solution for y^'cos(x)+ysin(x)=2cos^3(x)sin(x) is y=-(cos(2x))/(2sec(x))+(c_{1})/(sec(x))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^'cos(x)+ysin(x)=2cos^3(x)sin(x)

y^{^{'}} cos (x) + y sin (x) = 2 cos^{3} (x) sin (x)

y = - \frac{cos ( 2 x )}{2 sec ( x )} + \frac{c _{1}}{sec ( x )}

Solution steps

y^{'} (x) cos (x) + y sin (x) = 2 cos^{3} (x) sin (x)

Solve linear ODE:

y = - \frac{cos ( 2 x )}{2 sec ( x )} + \frac{c _{1}}{sec ( x )}

y = - \frac{cos ( 2 x )}{2 sec ( x )} + \frac{c _{1}}{sec ( x )}

h \to 0 lim (\frac{2 ^{- h} - 1}{h})

arcsin (\frac{x}{3}) + C

\int \frac{54}{( 9 x + 5 ) ^{7}} d x

\int 6 sin^{2} (3 x) d x

f (x) = \frac{1 - 5 x}{1 + 7 x}

What is the solution for y^'cos(x)+ysin(x)=2cos^3(x)sin(x) ?
The solution for y^'cos(x)+ysin(x)=2cos^3(x)sin(x) is y=-(cos(2x))/(2sec(x))+(c_{1})/(sec(x))