What is the derivative of x^3+x^{1/2}+2 ?

The derivative of x^3+x^{1/2}+2 is (1+6x^{5/2})/(2x^{1/2)}

What is the first derivative of x^3+x^{1/2}+2 ?

The first derivative of x^3+x^{1/2}+2 is (1+6x^{5/2})/(2x^{1/2)}

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\frac{d}{d x} (x^{3} + x^{\frac{1}{2}} + 2)

\frac{1 + 6 x ^{\frac{5}{2}}}{2 x ^{\frac{1}{2}}}

Solution steps

\frac{d}{d x} (x^{3} + x^{\frac{1}{2}} + 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) + \frac{d}{d x} (x^{\frac{1}{2}}) + \frac{d}{d x} (2)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (x^{\frac{1}{2}}) = \frac{1}{2 x ^{\frac{1}{2}}}

\frac{d}{d x} (2) = 0

= 3 x^{2} + \frac{1}{2 x ^{\frac{1}{2}}} + 0

Simplify

3 x^{2} + \frac{1}{2 x ^{\frac{1}{2}}} + 0 : \frac{1 + 6 x ^{\frac{5}{2}}}{2 x ^{\frac{1}{2}}}

= \frac{1 + 6 x ^{\frac{5}{2}}}{2 x ^{\frac{1}{2}}}

\frac{\partial}{\partial y} (\frac{2 x}{x ^{2} + y ^{4}})

f (x - π)

f (x) = tan (x) - 1

\frac{\partial}{\partial x} (5 e^{x} cos (yz))

\int_{0}^{1} (e^{- 2 x}) d x

What is the derivative of x^3+x^{1/2}+2 ?
The derivative of x^3+x^{1/2}+2 is (1+6x^{5/2})/(2x^{1/2)}
What is the first derivative of x^3+x^{1/2}+2 ?
The first derivative of x^3+x^{1/2}+2 is (1+6x^{5/2})/(2x^{1/2)}