What is the sum from n=1 to infinity of 1/(9n+3n-2) ?

The sum from n=1 to infinity of 1/(9n+3n-2) is diverges

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sum from n=1 to infinity of 1/(9n+3n-2)

n = 1 \sum \infty \frac{1}{9 n + 3 n - 2}

diverges

Solution steps

n = 1 \sum \infty \frac{1}{9 n + 3 n - 2}

Simplify

= n = 1 \sum \infty \frac{1}{12 n - 2}

Apply Series Comparison Test:

diverges

= diverges

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What is the sum from n=1 to infinity of 1/(9n+3n-2) ?
The sum from n=1 to infinity of 1/(9n+3n-2) is diverges