What is the tangent of x^2+9(-5.34) ?

The tangent of x^2+9(-5.34) is y=2a_{0}x-a_{0}^2-48.06

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tangent of x^2+9(-5.34)

tangent of

x^{2} + 9 (- 5.34)

y = 2 a_{0} x - a_{0}^{2} - 48.06

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, a_{0}^{2} - 48.06)

Find the slope of

y = x^{2} + 9 (- 5.34) : \frac{d y}{d x} = 2 x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 2 a_{0}

Find the line with slope m=

2 a_{0}

and passing through

(a_{0}, a_{0}^{2} - 48.06) : y = 2 a_{0} x - a_{0}^{2} - 48.06

y = 2 a_{0} x - a_{0}^{2} - 48.06

x \to 0 lim (3 x^{2} - 2 x + 4)

\frac{d}{d x} (15 x^{5} - \frac{60}{7 x ^{6}} - 1)

\int \frac{r}{( r ^{2} + z ^{2} ) ^{\frac{3}{2}}} d r

\frac{d}{d x} (\frac{- 4 x}{x ^{4} - 2 x ^{2} + 1})

x \to a lim (f (x) (x)^{g (x)})

What is the tangent of x^2+9(-5.34) ?
The tangent of x^2+9(-5.34) is y=2a_{0}x-a_{0}^2-48.06