What is the integral of pi/2-5x^{-0.5} ?

The integral of pi/2-5x^{-0.5} is pi/2 x-10sqrt(x)+C

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integral of pi/2-5x^{-0.5}

\int \frac{π}{2} - 5 x^{- 0.5} d x

\frac{π}{2} x - 10 x + C

Solution steps

\int \frac{π}{2} - 5 x^{- 0.5} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{π}{2} d x - \int 5 x^{- 0.5} d x

\int \frac{π}{2} d x = \frac{π}{2} x

\int 5 x^{- 0.5} d x = 10 x

= \frac{π}{2} x - 10 x

Add a constant to the solution

= \frac{π}{2} x - 10 x + C

\frac{d ^{3}}{d x ^{3}} (x^{4} - 8 x^{3})

\frac{d}{d x} (e^{c o s (x + 3)})

- 8 t^{2} y^{^{''}} - 4 t (t - 4) y^{^{'}} + 4 (t - 4) y = 0

y^{2} = x, x - 2 y = 3

\frac{d}{d x} (3 x (x^{2} - x + 1) (5 x - 3))

What is the integral of pi/2-5x^{-0.5} ?
The integral of pi/2-5x^{-0.5} is pi/2 x-10sqrt(x)+C