What is the limit as x approaches 0 of (sin^2(2x))/x ?

The limit as x approaches 0 of (sin^2(2x))/x is 0

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limit as x approaches 0 of (sin^2(2x))/x

x \to 0 lim (\frac{sin ^{2} ( 2 x )}{x})

0

Solution steps

x \to 0 lim (\frac{sin ^{2} ( 2 x )}{x})

Apply L'Hopital's Rule

: x \to 0 lim (\frac{2 sin ( 4 x )}{1})

= x \to 0 lim (\frac{2 sin ( 4 x )}{1})

Plug in the value

x = 0

= \frac{2 sin ( 4 \cdot 0 )}{1}

Simplify

\frac{2 sin ( 4 \cdot 0 )}{1} : 0

= 0

f (x) = tan (e^{x})

\frac{x ^{2} - 5 x}{x + 1}

n = 0 \sum \infty \frac{5 ^{n}}{n !}

\int 8 e^{- 2 x} d x

x^{2} cos (x), π

What is the limit as x approaches 0 of (sin^2(2x))/x ?
The limit as x approaches 0 of (sin^2(2x))/x is 0