What is the derivative of 8/(7x^2) ?

The derivative of 8/(7x^2) is -(16)/(7x^3)

What is the first derivative of 8/(7x^2) ?

The first derivative of 8/(7x^2) is -(16)/(7x^3)

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derivative of

\frac{8}{7 x ^{2}}

- \frac{16}{7 x ^{3}}

Solution steps

\frac{d}{d x} (\frac{8}{7 x ^{2}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{8}{7} \frac{d}{d x} (\frac{1}{x ^{2}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{8}{7} \frac{d}{d x} (x^{- 2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{8}{7} (- 2 x^{- 2 - 1})

Simplify

\frac{8}{7} (- 2 x^{- 2 - 1}) : - \frac{16}{7 x ^{3}}

= - \frac{16}{7 x ^{3}}

(5 x^{6} + 8 x^{3})^{4}

\frac{2}{s ( 0.12 s + 1 )}

x y^{^{'}} = y + 7 x^{2} sin (x)

\frac{\partial}{\partial x} (x y^{\frac{1}{2}})

R (t) = 50 t^{2} e^{- t} + 8

What is the derivative of 8/(7x^2) ?
The derivative of 8/(7x^2) is -(16)/(7x^3)
What is the first derivative of 8/(7x^2) ?
The first derivative of 8/(7x^2) is -(16)/(7x^3)