What is (\partial)/(\partial x)(6x^2-4xy^2) ?

The answer to (\partial)/(\partial x)(6x^2-4xy^2) is 12x-4y^2

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(\partial)/(\partial x)(6x^2-4xy^2)

\frac{\partial}{\partial x} (6 x^{2} - 4 x y^{2})

12 x - 4 y^{2}

Solution steps

\frac{\partial}{\partial x} (6 x^{2} - 4 x y^{2})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (6 x^{2}) - \frac{\partial}{\partial x} (4 x y^{2})

\frac{\partial}{\partial x} (6 x^{2}) = 12 x

\frac{\partial}{\partial x} (4 x y^{2}) = 4 y^{2}

= 12 x - 4 y^{2}

f (- 1) = \frac{x + 3}{2}

\frac{\partial}{\partial x} (ln (1 - x - y) - x^{- 1} - y^{- 1})

f (x) = e^{- 5 x}

y = x + 10

\frac{( 5 )}{s ^{2} - 9}

What is (\partial)/(\partial x)(6x^2-4xy^2) ?
The answer to (\partial)/(\partial x)(6x^2-4xy^2) is 12x-4y^2