What is the d/(dθ)(4cos(θ)) ?

The d/(dθ)(4cos(θ)) is -4sin(θ)

What is the first d/(dθ)(4cos(θ)) ?

The first d/(dθ)(4cos(θ)) is -4sin(θ)

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\frac{d}{d θ} (4 cos (θ))

- 4 sin (θ)

Solution steps

\frac{d}{d θ} (4 cos (θ))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{d}{d θ} (cos (θ))

Apply the common derivative:

\frac{d}{d θ} (cos (θ)) = - sin (θ)

= 4 (- sin (θ))

Simplify

= - 4 sin (θ)

\frac{d}{d x} (\frac{x ^{2} - 1}{( x - 1 ) ^{2}})

y^{^{'}} = x y

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