What is area y=x,y=1-x^2,-1,2 ?

The answer to area y=x,y=1-x^2,-1,2 is 3/2+(5sqrt(5)+7)/6

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area y=x,y=1-x^2,-1,2

area

y = x, y = 1 - x^{2}, - 1, 2

\frac{3}{2} + \frac{5 5 + 7}{6}

Decimal

4.53005 \dots

Solution steps

Apply the area formula:

\int_{- 1}^{2} x - (1 - x^{2}) d x

Solve

\int_{- 1}^{2} x - (1 - x^{2}) d x : \frac{3}{2} + \frac{5 5 + 7}{6}

The area is:

= \frac{3}{2} + \frac{5 5 + 7}{6}

- \frac{39}{( 8 x + 5 ) ^{2}}, at x = 2

\int_{0}^{4} \frac{12}{x ^{2} + 5 x + 6} d x

\int \frac{4}{x ^{2} + 8 x} d x

\frac{d}{d x} (x e^{x y} cos (2 x) - 3)

\int_{- 1}^{1} \frac{3 x}{( x + 6 ) ^{2}} d x

What is area y=x,y=1-x^2,-1,2 ?
The answer to area y=x,y=1-x^2,-1,2 is 3/2+(5sqrt(5)+7)/6