What is the integral of 3xsqrt(x) ?

The integral of 3xsqrt(x) is 6/5 x^{5/2}+C

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integral of 3xsqrt(x)

\int 3 x x d x

\frac{6}{5} x^{\frac{5}{2}} + C

Solution steps

\int 3 x x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int x x d x

Simplify

x x : x^{\frac{3}{2}}

= 3 \cdot \int x^{\frac{3}{2}} d x

Apply the Power Rule

: \frac{2}{5} x^{\frac{5}{2}}

= 3 \cdot \frac{2}{5} x^{\frac{5}{2}}

Simplify

3 \cdot \frac{2}{5} x^{\frac{5}{2}} : \frac{6}{5} x^{\frac{5}{2}}

= \frac{6}{5} x^{\frac{5}{2}}

Add a constant to the solution

= \frac{6}{5} x^{\frac{5}{2}} + C

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y = x^{3} (3 - x^{2})

\frac{\partial}{\partial x} (sin (π (4 x - 2 y)))