What is the derivative of x^4+12x^2+42 ?

The derivative of x^4+12x^2+42 is 4x^3+24x

What is the first derivative of x^4+12x^2+42 ?

The first derivative of x^4+12x^2+42 is 4x^3+24x

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\frac{d}{d x} (x^{4} + 12 x^{2} + 42)

4 x^{3} + 24 x

Solution steps

\frac{d}{d x} (x^{4} + 12 x^{2} + 42)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{4}) + \frac{d}{d x} (12 x^{2}) + \frac{d}{d x} (42)

\frac{d}{d x} (x^{4}) = 4 x^{3}

\frac{d}{d x} (12 x^{2}) = 24 x

\frac{d}{d x} (42) = 0

= 4 x^{3} + 24 x + 0

Simplify

= 4 x^{3} + 24 x

\frac{d}{d x} (\frac{6 x}{2 + x ^{2}})

x y^{^{'}} = 2 y + x^{3}

\int \frac{sin ( 4 x )}{cos ^{3} ( 4 x )} d x

\frac{\partial}{\partial x} (k)

\frac{d}{d x} ((3 x - 3 x^{2}) tan (x))

What is the derivative of x^4+12x^2+42 ?
The derivative of x^4+12x^2+42 is 4x^3+24x
What is the first derivative of x^4+12x^2+42 ?
The first derivative of x^4+12x^2+42 is 4x^3+24x