What is (\partial)/(\partial y)(3x^4y^2+3) ?

The answer to (\partial)/(\partial y)(3x^4y^2+3) is 6x^4y

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial y)(3x^4y^2+3)

\frac{\partial}{\partial y} (3 x^{4} y^{2} + 3)

6 x^{4} y

Solution steps

\frac{\partial}{\partial y} (3 x^{4} y^{2} + 3)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (3 x^{4} y^{2}) + \frac{\partial}{\partial y} (3)

\frac{\partial}{\partial y} (3 x^{4} y^{2}) = 6 x^{4} y

\frac{\partial}{\partial y} (3) = 0

= 6 x^{4} y + 0

Simplify

= 6 x^{4} y

y^{3} y^{^{'}} + x^{3} = 0

x^{2} + 2 x

\int (6 x^{2} - 8 x + 2) d x

y^{^{'''}} + y^{^{'}} = cot (x)

y^{^{''}} + 5 \frac{d y}{d x} + 6 y = 2 e^{x}

What is (\partial)/(\partial y)(3x^4y^2+3) ?
The answer to (\partial)/(\partial y)(3x^4y^2+3) is 6x^4y