What is the integral of 15xsqrt(x+1) ?

The integral of 15xsqrt(x+1) is 15(2/5 (x+1)^{5/2}-2/3 (x+1)^{3/2})+C

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integral of 15xsqrt(x+1)

\int 15 x x + 1 d x

15 (\frac{2}{5} (x + 1)^{\frac{5}{2}} - \frac{2}{3} (x + 1)^{\frac{3}{2}}) + C

Solution steps

\int 15 x x + 1 d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 15 \cdot \int x x + 1 d x

Apply u-substitution

: \int (u - 1) u d u

= 15 \cdot \int (u - 1) u d u

Expand

(u - 1) u : u^{\frac{3}{2}} - u

= 15 \cdot \int u^{\frac{3}{2}} - u d u

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= 15 (\int u^{\frac{3}{2}} d u - \int u d u)

\int u^{\frac{3}{2}} d u = \frac{2}{5} u^{\frac{5}{2}}

\int u d u = \frac{2}{3} u^{\frac{3}{2}}

= 15 (\frac{2}{5} u^{\frac{5}{2}} - \frac{2}{3} u^{\frac{3}{2}})

Substitute back

u = x + 1

= 15 (\frac{2}{5} (x + 1)^{\frac{5}{2}} - \frac{2}{3} (x + 1)^{\frac{3}{2}})

Add a constant to the solution

= 15 (\frac{2}{5} (x + 1)^{\frac{5}{2}} - \frac{2}{3} (x + 1)^{\frac{3}{2}}) + C

n = 2 \sum \infty \frac{1}{n ^{3} - n}

y = ln (x^{13})

\int \frac{x ^{2} - 3 x - 1}{x ( x ^{2} + 4 )} d x

x^{- 2}

\int 1 - x^{- 0.52} d x

What is the integral of 15xsqrt(x+1) ?
The integral of 15xsqrt(x+1) is 15(2/5 (x+1)^{5/2}-2/3 (x+1)^{3/2})+C