What is the integral of-t^{3/2} ?

The integral of-t^{3/2} is -2/5 t^{5/2}+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of-t^{3/2}

\int - t^{\frac{3}{2}} d t

- \frac{2}{5} t^{\frac{5}{2}} + C

Solution steps

\int - t^{\frac{3}{2}} d t

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int t^{\frac{3}{2}} d t

Apply the Power Rule

: \frac{2}{5} t^{\frac{5}{2}}

= - \frac{2}{5} t^{\frac{5}{2}}

Add a constant to the solution

= - \frac{2}{5} t^{\frac{5}{2}} + C

10 e^{x}

\int_{2}^{3} \frac{x}{x ^{2} - 1} d x

\int \frac{ln ( x )}{1 + x ^{2}} d x

\int ln (\frac{x}{x + 2}) d x

\frac{d}{d x} (x^{5} - 4 x^{3} + x - 1)