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Popular >

y^'=e^{-y}

Solution

y^{^{'}} = e^{- y}

Solution

y = ln (t + c_{1})

Solution steps

y^{'} (t) = e^{- y}

Solve separable ODE:

y = ln (t + c_{1})

y = ln (t + c_{1})

Graph

Popular Examples

derivative of arctan(6x)

\frac{d}{d x} (arctan (6 x))

integral from 0 to pi of (8e^x+5sin(x))

\int_{0}^{π} (8 e^{x} + 5 sin (x)) d x

integral from 1 to 2 of 4r^4ln(r)

\int_{1}^{2} 4 r^{4} ln (r) d r

tangent of y=2sqrt(x)+1 tangent of

y = 2 x + 1

y^'+3/x y=0,y(1)=5

y^{^{'}} + \frac{3}{x} y = 0, y (1) = 5

Frequently Asked Questions (FAQ)

What is the solution for y^'=e^{-y} ?
The solution for y^'=e^{-y} is y=ln(t+c_{1})