What is the integral from 0 to pi/6 of sec^2(x) ?

The integral from 0 to pi/6 of sec^2(x) is 1/(sqrt(3))

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integral from 0 to pi/6 of sec^2(x)

\int_{0}^{\frac{π}{6}} sec^{2} (x) d x

\frac{1}{3}

Decimal

0.57735 \dots

Solution steps

\int_{0}^{\frac{π}{6}} sec^{2} (x) d x

Use the common integral:

\int sec^{2} (x) d x = tan (x)

= [tan (x)]_{0}^{\frac{π}{6}}

Compute the boundaries:

\frac{1}{3}

= \frac{1}{3}

f (x) = x^{3} + 2 x

\frac{\partial}{\partial x} (x e^{x y} + \frac{x}{y ^{2}})

f (x) = x, at x = 64

4 x y y^{^{'}} = 4 y^{2} + 3 x x^{2} + y^{2}

\int (\frac{5}{x} + \frac{12}{x ^{5}}) d x

What is the integral from 0 to pi/6 of sec^2(x) ?
The integral from 0 to pi/6 of sec^2(x) is 1/(sqrt(3))