What is the sum from n=0 to infinity of (-4/9)^n ?

The sum from n=0 to infinity of (-4/9)^n is 9/13

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sum from n=0 to infinity of (-4/9)^n

n = 0 \sum \infty (- \frac{4}{9})^{n}

\frac{9}{13}

Solution steps

n = 0 \sum \infty (- \frac{4}{9})^{n}

Apply Series Geometric Test:

\frac{9}{13}

= \frac{9}{13}

y = x^{\frac{1}{2}}, x = 0, x = 1

n = 1 \sum \infty \frac{5}{e ^{2 n}}

\frac{x y}{x + y}

\int + x^{2} \cdot + sin (x) d x

x^{^{''}} - 3 x^{^{'}} = e^{3 t}

What is the sum from n=0 to infinity of (-4/9)^n ?
The sum from n=0 to infinity of (-4/9)^n is 9/13