What is the derivative of sin^2(3x+1) ?

The derivative of sin^2(3x+1) is 6sin(3x+1)cos(3x+1)

What is the first derivative of sin^2(3x+1) ?

The first derivative of sin^2(3x+1) is 6sin(3x+1)cos(3x+1)

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\frac{d}{d x} (sin^{2} (3 x + 1))

6 sin (3 x + 1) cos (3 x + 1)

Solution steps

\frac{d}{d x} (sin^{2} (3 x + 1))

Apply the chain rule:

2 sin (3 x + 1) \frac{d}{d x} (sin (3 x + 1))

= 2 sin (3 x + 1) \frac{d}{d x} (sin (3 x + 1))

\frac{d}{d x} (sin (3 x + 1)) = cos (3 x + 1) \cdot 3

= 2 sin (3 x + 1) cos (3 x + 1) \cdot 3

Simplify

= 6 sin (3 x + 1) cos (3 x + 1)

x \to 3 lim ((x - 3) ln (x - 3))

\int e^{- \frac{x}{y l n ( 2 )}} d x

\int (\frac{5 x ^{3} - 3}{x}) d x

\frac{8.75}{S + \frac{2}{3}}

\frac{d}{d x} (\frac{2 x + 5}{x ^{2} + 5 x})

What is the derivative of sin^2(3x+1) ?
The derivative of sin^2(3x+1) is 6sin(3x+1)cos(3x+1)
What is the first derivative of sin^2(3x+1) ?
The first derivative of sin^2(3x+1) is 6sin(3x+1)cos(3x+1)