What is the derivative of f(x)=x^2+4x ?

The derivative of f(x)=x^2+4x is 2x+4

What is the first derivative of f(x)=x^2+4x ?

The first derivative of f(x)=x^2+4x is 2x+4

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derivative of

f (x) = x^{2} + 4 x

2 x + 4

Solution steps

\frac{d}{d x} (x^{2} + 4 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (4 x)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (4 x) = 4

= 2 x + 4

f (x) = 2 x - cot^{2} (x)

y = \frac{1}{x + 1}

f (x) = 1260 - 16 x^{2}, at x = 3

f (x) = x^{\frac{19}{9}} + x^{\frac{10}{9}}

\int x z d y

What is the derivative of f(x)=x^2+4x ?
The derivative of f(x)=x^2+4x is 2x+4
What is the first derivative of f(x)=x^2+4x ?
The first derivative of f(x)=x^2+4x is 2x+4