What is the derivative of (u^2+u)^3 ?

The derivative of (u^2+u)^3 is 3(u^2+u)^2(2u+1)

What is the first derivative of (u^2+u)^3 ?

The first derivative of (u^2+u)^3 is 3(u^2+u)^2(2u+1)

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derivative of

(u^{2} + u)^{3}

3 (u^{2} + u)^{2} (2 u + 1)

Solution steps

\frac{d}{d u} ((u^{2} + u)^{3})

Apply the chain rule:

3 (u^{2} + u)^{2} \frac{d}{d u} (u^{2} + u)

= 3 (u^{2} + u)^{2} \frac{d}{d u} (u^{2} + u)

\frac{d}{d u} (u^{2} + u) = 2 u + 1

= 3 (u^{2} + u)^{2} (2 u + 1)

csc (3 x) cot (3 x)

\int sin^{3} (x) sin (2 x) d x

y = 2 x^{3} + 3 x^{2} - 12 x + 4

x \to - 2 - lim (\frac{1}{( x + 2 ) ^{2}})

x \to 3 lim (\frac{4 x + 2}{x + 4})

What is the derivative of (u^2+u)^3 ?
The derivative of (u^2+u)^3 is 3(u^2+u)^2(2u+1)
What is the first derivative of (u^2+u)^3 ?
The first derivative of (u^2+u)^3 is 3(u^2+u)^2(2u+1)