What is implicit (dy)/(dx),(x-1)^2+(y+4)^2=25 ?

The answer to implicit (dy)/(dx),(x-1)^2+(y+4)^2=25 is (dy)/(dx)=(-x+1)/(4+y)

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implicit (dy)/(dx),(x-1)^2+(y+4)^2=25

implicit derivative

\frac{d y}{d x}, (x - 1)^{2} + (y + 4)^{2} = 25

\frac{d y}{d x} = \frac{- x + 1}{4 + y}

Solution steps

(x - 1)^{2} + (y + 4)^{2} = 25

Treat

y

y (x)

Differentiate both sides:

2 x + 2 y \frac{d y}{d x} + 8 \frac{d y}{d x} - 2 = 0

Isolate

\frac{d y}{d x} : \frac{d y}{d x} = \frac{- x + 1}{4 + y}

\frac{d y}{d x} = \frac{- x + 1}{4 + y}

y^{^{'}} - y = 2 x e^{2 x}, y (0) = 1

f (4)

\frac{8 x ^{2} + 2 x + 2}{x}

\int x 7^{x^{2}} d x

y^{^{''}} + 14 \cdot 2 y^{^{'}} + 49 y = 0, y (0) = 0, y^{^{'}} (0) = 1

What is implicit (dy)/(dx),(x-1)^2+(y+4)^2=25 ?
The answer to implicit (dy)/(dx),(x-1)^2+(y+4)^2=25 is (dy)/(dx)=(-x+1)/(4+y)