What is the integral of (10)/(x^9) ?

The integral of (10)/(x^9) is -5/(4x^8)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (10)/(x^9)

\int \frac{10}{x ^{9}} d x

- \frac{5}{4 x ^{8}} + C

Solution steps

\int \frac{10}{x ^{9}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 10 \cdot \int \frac{1}{x ^{9}} d x

Apply the Power Rule

: - \frac{1}{8 x ^{8}}

= 10 (- \frac{1}{8 x ^{8}})

Simplify

10 (- \frac{1}{8 x ^{8}}) : - \frac{5}{4 x ^{8}}

= - \frac{5}{4 x ^{8}}

Add a constant to the solution

= - \frac{5}{4 x ^{8}} + C

f (x) = x^{4} - 1 3^{2} + 36, at x = - 2

\frac{d}{d x} (arcsin (\frac{y}{x}))

\frac{\partial}{\partial x} (x y e^{x + 2 y})

\frac{d}{d x} (2 x - \frac{1}{x ^{2}})

\frac{d y}{d t}, y = e^{t}