What is the integral of sqrt(sec^2(x)) ?

The integral of sqrt(sec^2(x)) is ln|tan(x)+sec(x)|+C

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integral of sqrt(sec^2(x))

\int sec^{2} (x) d x

ln ∣ tan (x) + sec (x) ∣ + C

Solution steps

\int sec^{2} (x) d x

sec^{2} (x) = (sec (x)),

assuming

sec (x) \geq 0

= \int sec (x) d x

Use the common integral:

\int sec (x) d x = ln ∣ tan (x) + sec (x) ∣

= ln ∣ tan (x) + sec (x) ∣

Add a constant to the solution

= ln ∣ tan (x) + sec (x) ∣ + C

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f (x) = \frac{- 3 x + 1}{x ^{2} - x}

y = \frac{ln ( x )}{x ^{5}}

\int \frac{e ^{3 t}}{t} d t

\int in (x) d x

What is the integral of sqrt(sec^2(x)) ?
The integral of sqrt(sec^2(x)) is ln|tan(x)+sec(x)|+C