What is the d/(dθ)(2-sin(θ)) ?

The d/(dθ)(2-sin(θ)) is -cos(θ)

What is the first d/(dθ)(2-sin(θ)) ?

The first d/(dθ)(2-sin(θ)) is -cos(θ)

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\frac{d}{d θ} (2 - sin (θ))

- cos (θ)

Solution steps

\frac{d}{d θ} (2 - sin (θ))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d θ} (2) - \frac{d}{d θ} (sin (θ))

\frac{d}{d θ} (2) = 0

\frac{d}{d θ} (sin (θ)) = cos (θ)

= 0 - cos (θ)

Simplify

= - cos (θ)

x e^{- x + 1}, at 1

y = \frac{- 2 x}{x ^{2} + 1}, (- 1, 1)

x \to π lim (x^{2} cos (x))

n = 0 \sum \infty \frac{n}{2}

n = 2 \sum \infty \frac{1}{e ^{n}}