What is the integral of 3sec(x)tan(x) ?

The integral of 3sec(x)tan(x) is 3sec(x)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of 3sec(x)tan(x)

\int 3 sec (x) tan (x) d x

3 sec (x) + C

Solution steps

\int 3 sec (x) tan (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int sec (x) tan (x) d x

Apply u-substitution

: \int 1 d u

= 3 \cdot \int 1 d u

Integral of a constant:

\int a d x = a x

= 3 \cdot 1 \cdot u

Substitute back

u = sec (x)

= 3 \cdot 1 \cdot sec (x)

Simplify

= 3 sec (x)

Add a constant to the solution

= 3 sec (x) + C

\int 4 sec (2 x) tan (2 x) d x

y = 2 x + 4

\frac{48}{x}

\frac{d}{d x} (1 + 2 x^{\frac{3}{2}})

\int \frac{x ^{2}}{2 x + 1} d x

What is the integral of 3sec(x)tan(x) ?
The integral of 3sec(x)tan(x) is 3sec(x)+C