What is the tangent of f(x)=-5cos(x),\at x= pi/2 ?

The tangent of f(x)=-5cos(x),\at x= pi/2 is y=5x-(5pi)/2

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tangent of f(x)=-5cos(x),\at x= pi/2

tangent of

f (x) = - 5 cos (x), at x = \frac{π}{2}

y = 5 x - \frac{5 π}{2}

Solution steps

Find the tangent point:

(\frac{π}{2}, 0)

Find the slope of

f (x) = - 5 cos (x) : \frac{df ( x )}{d x} = 5 sin (x)

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 5

Find the line with slope m=

5

and passing through

(\frac{π}{2}, 0) : y = 5 x - \frac{5 π}{2}

y = 5 x - \frac{5 π}{2}

\int \frac{3}{x} + \frac{2}{x ^{2}} d x

\frac{d y}{d x} = \frac{( x - 1 )}{( y - 4 )}

\int_{2}^{\infty} \frac{3}{x ^{2} - x} d x

y = x^{3} - x, y = 7 x - x^{3}

\frac{\partial}{\partial y} (6 ln (6 x^{3} + y^{2}))

What is the tangent of f(x)=-5cos(x),\at x= pi/2 ?
The tangent of f(x)=-5cos(x),\at x= pi/2 is y=5x-(5pi)/2