What is the solution for 3y^3dx-6x^4dy=0 ?

The solution for 3y^3dx-6x^4dy=0 is y=sqrt(-(3x^3)/(-1+6c_{1)x^3)},y=-sqrt(-(3x^3)/(-1+6c_{1)x^3)}

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3y^3dx-6x^4dy=0

3 y^{3} d x - 6 x^{4} d y = 0

y = - \frac{3 x ^{3}}{- 1 + 6 c _{1} x ^{3}}, y = - - \frac{3 x ^{3}}{- 1 + 6 c _{1} x ^{3}}

Solution steps

3 y^{3} d x - 6 x^{4} d y = 0

Solve separable ODE:

y = - \frac{3 x ^{3}}{- 1 + 6 c _{1} x ^{3}}, y = - - \frac{3 x ^{3}}{- 1 + 6 c _{1} x ^{3}}

y = - \frac{3 x ^{3}}{- 1 + 6 c _{1} x ^{3}}, y = - - \frac{3 x ^{3}}{- 1 + 6 c _{1} x ^{3}}

\frac{d}{d x} (\frac{7 - sec ( x )}{tan ( x )})

\frac{d}{d x} ((- x^{2} + 4 x + 5) (4 x^{4} - 3))

\frac{d x}{d t} = 3 x t^{3}

\frac{d y}{d x} - \frac{2 y}{x} = x^{2} - 1

x \to 4 + lim (2 x - 9)

What is the solution for 3y^3dx-6x^4dy=0 ?
The solution for 3y^3dx-6x^4dy=0 is y=sqrt(-(3x^3)/(-1+6c_{1)x^3)},y=-sqrt(-(3x^3)/(-1+6c_{1)x^3)}