What is the sum from n=1 to infinity of 8/(n^4) ?

The sum from n=1 to infinity of 8/(n^4) is converges

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sum from n=1 to infinity of 8/(n^4)

n = 1 \sum \infty \frac{8}{n ^{4}}

converges

Solution steps

n = 1 \sum \infty \frac{8}{n ^{4}}

Apply the constant multiplication rule:

\sum c \cdot a_{n} = c \cdot \sum a_{n}

= 8 \cdot n = 1 \sum \infty \frac{1}{n ^{4}}

Apply p-Series Test:

converges

= 8 converges

= converges

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147.456 π t

\frac{\partial}{\partial x} (x^{2} y^{3} + 2 x y^{- 3} + 5 x + 3 y + 11)

t \to 5 lim (\frac{1}{t ^{2} - 4 t - 5} - \frac{1}{6 ( t - 5 )})

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What is the sum from n=1 to infinity of 8/(n^4) ?
The sum from n=1 to infinity of 8/(n^4) is converges