What is the limit as x approaches 0 of 8/(1+sin(x)) ?

The limit as x approaches 0 of 8/(1+sin(x)) is 8

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limit as x approaches 0 of 8/(1+sin(x))

x \to 0 lim (\frac{8}{1 + sin ( x )})

8

Solution steps

x \to 0 lim (\frac{8}{1 + sin ( x )})

Plug in the value

x = 0

= \frac{8}{1 + sin ( 0 )}

Simplify

\frac{8}{1 + sin ( 0 )} : 8

= 8

\frac{d}{d x} (\frac{4 x}{x ^{2} + 1})

\frac{lo g _{5} ( x )}{6 + x ^{5}}

\frac{\partial}{\partial x} (y cos (y - 2 x))

\int \frac{- y}{y} d y

y^{^{'}} + 2 x (y + 1) = 0

What is the limit as x approaches 0 of 8/(1+sin(x)) ?
The limit as x approaches 0 of 8/(1+sin(x)) is 8