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Popular >

((x^2}{100}+8+\frac{20)/x)^'

Solution

(\frac{x ^{2}}{100} + 8 + \frac{20}{x})^{^{'}}

Solution

\frac{x}{50} - \frac{20}{x ^{2}}

Solution steps

(\frac{x ^{2}}{100} + 8 + \frac{20}{x})^{'}

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= (\frac{x ^{2}}{100})^{^{'}} + 8^{^{'}} + (\frac{20}{x})^{^{'}}

(\frac{x ^{2}}{100})^{'} = \frac{x}{50}

8^{'} = 0

(\frac{20}{x})^{'} = - \frac{20}{x ^{2}}

= \frac{x}{50} + 0 - \frac{20}{x ^{2}}

Simplify

= \frac{x}{50} - \frac{20}{x ^{2}}

Graph

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Frequently Asked Questions (FAQ)

What is the ((x^2}{100}+8+\frac{20)/x)^' ?
The ((x^2}{100}+8+\frac{20)/x)^' is x/(50)-(20)/(x^2)
What is the first ((x^2}{100}+8+\frac{20)/x)^' ?
The first ((x^2}{100}+8+\frac{20)/x)^' is x/(50)-(20)/(x^2)