What is the tangent of f(x)=(3x)/(x^2-6),3,\at x=3 ?

The tangent of f(x)=(3x)/(x^2-6),3,\at x=3 is y=-5x+18

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tangent of f(x)=(3x)/(x^2-6),3,\at x=3

tangent of

f (x) = \frac{3 x}{x ^{2} - 6}, 3, at x = 3

y = - 5 x + 18

Solution steps

Find the tangent point:

(3, 3)

Find the slope of

f (x) = \frac{3 x}{x ^{2} - 6} : \frac{df ( x )}{d x} = \frac{3 ( - x ^{2} - 6 )}{( x ^{2} - 6 ) ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 5

Find the line with slope m=

- 5

and passing through

(3, 3) : y = - 5 x + 18

y = - 5 x + 18

\frac{8 5}{15} x^{\frac{3}{2}} - 2

\int cos^{3} (7 x) sin^{- 2} (7 x) d x

x^{^{'}} = - x

\int (- 7 x) d x

\int_{- 2}^{3} \frac{5}{x ^{4}} d x

What is the tangent of f(x)=(3x)/(x^2-6),3,\at x=3 ?
The tangent of f(x)=(3x)/(x^2-6),3,\at x=3 is y=-5x+18