What is the integral from 0.6 to 1.5 of (48+8y)/(81) ?

The integral from 0.6 to 1.5 of (48+8y)/(81) is 0.62666…

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integral from 0.6 to 1.5 of (48+8y)/(81)

\int_{0.6}^{1.5} \frac{48 + 8 y}{81} d y

0.62666 \dots

Solution steps

\int_{0.6}^{1.5} \frac{48 + 8 y}{81} d y

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{81} \cdot \int_{0.6}^{1.5} 48 + 8 y d y

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \frac{1}{81} (\int_{0.6}^{1.5} 48 d y + \int_{0.6}^{1.5} 8 y d y)

\int_{0.6}^{1.5} 48 d y = 43.2

\int_{0.6}^{1.5} 8 y d y = 7.56

= \frac{1}{81} (43.2 + 7.56)

Simplify

\frac{1}{81} (43.2 + 7.56) : 0.62666 \dots

= 0.62666 \dots

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What is the integral from 0.6 to 1.5 of (48+8y)/(81) ?
The integral from 0.6 to 1.5 of (48+8y)/(81) is 0.62666…