What is the derivative of x+4/(x+3) ?

The derivative of x+4/(x+3) is 1-4/((x+3)^2)

What is the first derivative of x+4/(x+3) ?

The first derivative of x+4/(x+3) is 1-4/((x+3)^2)

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\frac{d}{d x} (x + \frac{4}{x + 3})

1 - \frac{4}{( x + 3 ) ^{2}}

Solution steps

\frac{d}{d x} (x + \frac{4}{x + 3})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d x}{d x} + \frac{d}{d x} (\frac{4}{x + 3})

\frac{d x}{d x} = 1

\frac{d}{d x} (\frac{4}{x + 3}) = - \frac{4}{( x + 3 ) ^{2}}

= 1 - \frac{4}{( x + 3 ) ^{2}}

\frac{d}{d x} ((tan (x))^{x})

\frac{d y}{d x} = \frac{cos ( 6 x )}{e ^{6 y}}

\frac{d y}{d x} = \frac{3 x}{y + x ^{2} y}

\frac{\partial}{\partial x} (\frac{x - y}{x ^{2} + y ^{2}})

\int \frac{1 - x}{x ^{2} + 3 x + 2} d x

What is the derivative of x+4/(x+3) ?
The derivative of x+4/(x+3) is 1-4/((x+3)^2)
What is the first derivative of x+4/(x+3) ?
The first derivative of x+4/(x+3) is 1-4/((x+3)^2)