What is the solution for (x-y+2)dx-(x-y)dy=0 ?

The solution for (x-y+2)dx-(x-y)dy=0 is y=(2x+sqrt(-16x+c_{1)})/2 ,y=(2x-sqrt(-16x+c_{1)})/2

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(x-y+2)dx-(x-y)dy=0

(x - y + 2) d x - (x - y) d y = 0

y = \frac{2 x + - 16 x + c _{1}}{2}, y = \frac{2 x - - 16 x + c _{1}}{2}

Solution steps

(x - y + 2) d x - (x - y) d y = 0

Solve exact ODE:

y = \frac{2 x + - 16 x + c _{1}}{2}, y = \frac{2 x - - 16 x + c _{1}}{2}

y = \frac{2 x + - 16 x + c _{1}}{2}, y = \frac{2 x - - 16 x + c _{1}}{2}

x \to 0 lim ((1 + 2 x)^{\frac{5}{x}})

2 x^{3} + 2 x y + 2 y^{2} = 38, (- 1, - 4)

x \to 0 lim (\frac{sin ( x )}{x} - 1)

\int_{2}^{5} \frac{1}{x - 2} d x

f (x) = (2 x^{3} + 5 x) (x - 3) (x + 2)

What is the solution for (x-y+2)dx-(x-y)dy=0 ?
The solution for (x-y+2)dx-(x-y)dy=0 is y=(2x+sqrt(-16x+c_{1)})/2 ,y=(2x-sqrt(-16x+c_{1)})/2