What is the tangent of y=-3cos(x),\at x=(3pi)/4 ?

The tangent of y=-3cos(x),\at x=(3pi)/4 is y= 3/(sqrt(2))x+3/(sqrt(2))-(9pi)/(4sqrt(2))

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tangent of y=-3cos(x),\at x=(3pi)/4

tangent of

y = - 3 cos (x), at x = \frac{3 π}{4}

y = \frac{3}{2} x + \frac{3}{2} - \frac{9 π}{4 2}

Solution steps

Find the tangent point:

(\frac{3 π}{4}, \frac{3}{2})

Find the slope of

y = - 3 cos (x) : \frac{d y}{d x} = 3 sin (x)

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = \frac{3}{2}

Find the line with slope m=

\frac{3}{2}

and passing through

(\frac{3 π}{4}, \frac{3}{2}) : y = \frac{3}{2} x + \frac{3}{2} - \frac{9 π}{4 2}

y = \frac{3}{2} x + \frac{3}{2} - \frac{9 π}{4 2}

\int (x + 1)^{3} d x

\frac{d}{d x} (\frac{2 x}{x ^{2} - 1})

x \to 0 - lim (- x)

f (x) = e^{1 - x}

\frac{\partial}{\partial x} (6 e^{x y + 3})

What is the tangent of y=-3cos(x),\at x=(3pi)/4 ?
The tangent of y=-3cos(x),\at x=(3pi)/4 is y= 3/(sqrt(2))x+3/(sqrt(2))-(9pi)/(4sqrt(2))