What is the limit as x approaches 0 of 1/(9-3^{1/x)} ?

The limit as x approaches 0 of 1/(9-3^{1/x)} is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 0 of 1/(9-3^{1/x)}

x \to 0 lim (\frac{1}{9 - 3 ^{\frac{1}{x}}})

diverges

Solution steps

x \to 0 lim (\frac{1}{9 - 3 ^{\frac{1}{x}}})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (\frac{1}{9 - 3 ^{\frac{1}{x}}}) = 0

x \to 0 - lim (\frac{1}{9 - 3 ^{\frac{1}{x}}}) = \frac{1}{9}

= diverges

cos (8 θ)

\int - \frac{1}{9} cos (3 x) d x

\frac{\partial}{\partial x} (tan (2 x) sin (2 x))

f (x) = 4 x^{2} - 5 x

\frac{\partial}{\partial z} (cos (x z))

What is the limit as x approaches 0 of 1/(9-3^{1/x)} ?
The limit as x approaches 0 of 1/(9-3^{1/x)} is diverges