What is the derivative of 100-ln(2x+1) ?

The derivative of 100-ln(2x+1) is -2/(2x+1)

What is the first derivative of 100-ln(2x+1) ?

The first derivative of 100-ln(2x+1) is -2/(2x+1)

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\frac{d}{d x} (100 - ln (2 x + 1))

- \frac{2}{2 x + 1}

Solution steps

\frac{d}{d x} (100 - ln (2 x + 1))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (100) - \frac{d}{d x} (ln (2 x + 1))

\frac{d}{d x} (100) = 0

\frac{d}{d x} (ln (2 x + 1)) = \frac{2}{2 x + 1}

= 0 - \frac{2}{2 x + 1}

Simplify

= - \frac{2}{2 x + 1}

x \to 0 lim (+ (\frac{1}{x}))

\int_{- 1}^{1} \frac{1}{x ^{\frac{4}{5}}} d x

f (x) = (\frac{- 7}{7 x ^{2} + 1})

x \to 2 lim (\frac{2 + x}{x - 2})

x - 2 x^{2}, - 5 x

What is the derivative of 100-ln(2x+1) ?
The derivative of 100-ln(2x+1) is -2/(2x+1)
What is the first derivative of 100-ln(2x+1) ?
The first derivative of 100-ln(2x+1) is -2/(2x+1)