What is the solution for (dy)/(dx)-e^{2x+y}=0 ?

The solution for (dy)/(dx)-e^{2x+y}=0 is y=-ln(-1/2 e^{2x}-c_{1})

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(dy)/(dx)-e^{2x+y}=0

\frac{d y}{d x} - e^{2 x + y} = 0

y = - ln (- \frac{1}{2} e^{2 x} - c_{1})

Solution steps

\frac{d y}{d x} - e^{2 x + y} = 0

Solve separable ODE:

y = - ln (- \frac{1}{2} e^{2 x} - c_{1})

y = - ln (- \frac{1}{2} e^{2 x} - c_{1})

\frac{d}{d x} (a x^{3} + b x^{2} + c x)

\int \frac{( x ^{3} + 3 )}{x ^{2}} d x

\frac{\partial ^{2}}{\partial x \partial y} (x^{2} - e^{y^{2}})

\int_{0}^{y^{3}} x e^{\frac{- x}{y}} d x

\int - 2 - \frac{2}{x} d x

What is the solution for (dy)/(dx)-e^{2x+y}=0 ?
The solution for (dy)/(dx)-e^{2x+y}=0 is y=-ln(-1/2 e^{2x}-c_{1})