What is the derivative of-9sin(3x) ?

The derivative of-9sin(3x) is -27cos(3x)

What is the first derivative of-9sin(3x) ?

The first derivative of-9sin(3x) is -27cos(3x)

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\frac{d}{d x} (- 9 sin (3 x))

- 27 cos (3 x)

Solution steps

\frac{d}{d x} (- 9 sin (3 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 9 \frac{d}{d x} (sin (3 x))

Apply the chain rule:

cos (3 x) \frac{d}{d x} (3 x)

= cos (3 x) \frac{d}{d x} (3 x)

\frac{d}{d x} (3 x) = 3

= - 9 cos (3 x) \cdot 3

Simplify

= - 27 cos (3 x)

\frac{d}{d x} (tan (π - \frac{9}{x}))

\frac{d}{d x} (9 x^{9} e^{x - 1})

\int \frac{5}{x ln ( 3 x )} d x

x \to 6 - lim (7 - x)

\int \frac{1}{x ^{- 3}} d x

What is the derivative of-9sin(3x) ?
The derivative of-9sin(3x) is -27cos(3x)
What is the first derivative of-9sin(3x) ?
The first derivative of-9sin(3x) is -27cos(3x)