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Popular >

y^'=(x+y)/x

Solution

y^{^{'}} = \frac{x + y}{x}

Solution

y = ln (x) x + c_{1} x

Solution steps

y^{'} (x) = \frac{x + y}{x}

Solve linear ODE:

y = ln (x) x + c_{1} x

y = ln (x) x + c_{1} x

Graph

Popular Examples

derivative of x+a

\frac{d}{d x} (x + a)

derivative of 1-4x+sqrt({f)(x})

\frac{d}{d x} (1 - 4 x + f (x))

tangent of f(x)=2x^2,\at x=-2 tangent of

f (x) = 2 x^{2}, at x = - 2

(\partial)/(\partial y)(ln(x+y)-ln(x-y))

\frac{\partial}{\partial y} (ln (x + y) - ln (x - y))

tangent of y=sqrt(4x+48),(4,8)tangent of

y = 4 x + 48, (4, 8)

Frequently Asked Questions (FAQ)

What is the solution for y^'=(x+y)/x ?
The solution for y^'=(x+y)/x is y=ln(x)x+c_{1}x