What is the derivative of-0.5x^2+56x+20 ?

The derivative of-0.5x^2+56x+20 is -x+56

What is the first derivative of-0.5x^2+56x+20 ?

The first derivative of-0.5x^2+56x+20 is -x+56

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\frac{d}{d x} (- 0.5 x^{2} + 56 x + 20)

- x + 56

Solution steps

\frac{d}{d x} (- 0.5 x^{2} + 56 x + 20)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (0.5 x^{2}) + \frac{d}{d x} (56 x) + \frac{d}{d x} (20)

\frac{d}{d x} (0.5 x^{2}) = x

\frac{d}{d x} (56 x) = 56

\frac{d}{d x} (20) = 0

= - x + 56 + 0

Simplify

= - x + 56

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What is the derivative of-0.5x^2+56x+20 ?
The derivative of-0.5x^2+56x+20 is -x+56
What is the first derivative of-0.5x^2+56x+20 ?
The first derivative of-0.5x^2+56x+20 is -x+56