What is the solution for x^'=0.0333333x(30-x) ?

The solution for x^'=0.0333333x(30-x) is x=(0.999999)/(-e^{\frac{-c_{1)-t}{1.000001}}+0.0333333}

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x^'=0.0333333x(30-x)

x^{^{'}} = 0.0333333 x (30 - x)

x = \frac{0.999999}{- e ^{\frac{- c _{1} - t}{1.000001}} + 0.0333333}

Solution steps

x^{'} (t) = 0.0333333 x (30 - x)

Solve Bernoulli ODE:

x = \frac{0.999999}{- e ^{\frac{- c _{1} - t}{1.000001}} + 0.0333333}

x = \frac{0.999999}{- e ^{\frac{- c _{1} - t}{1.000001}} + 0.0333333}

x \to - 1 lim (\frac{x ^{2} - 5}{x + 6})

x \to 0 lim ((x + π) csc (x))

\int 42 x (x + 12)^{5} d x

f (x) = \frac{5 x}{x - 3}, at x = 4

\frac{\partial}{\partial x} (x - y - 1)

What is the solution for x^'=0.0333333x(30-x) ?
The solution for x^'=0.0333333x(30-x) is x=(0.999999)/(-e^{\frac{-c_{1)-t}{1.000001}}+0.0333333}