What is the tangent of f(x)=sin(x)+3,\at x=pi ?

The tangent of f(x)=sin(x)+3,\at x=pi is y=-x+3+pi

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tangent of f(x)=sin(x)+3,\at x=pi

tangent of

f (x) = sin (x) + 3, at x = π

y = - x + 3 + π

Solution steps

Find the tangent point:

(π, 3)

Find the slope of

f (x) = sin (x) + 3 : \frac{df ( x )}{d x} = cos (x)

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 1

Find the line with slope m=

- 1

and passing through

(π, 3) : y = - x + 3 + π

y = - x + 3 + π

8 x \cdot sin (x)

\int x^{3} + x^{- 4} + x^{\frac{3}{4}} d x

e^{10 x}

y^{^{'}} - 7 y = e^{x}

x \to 4 lim (\frac{- 2}{x ^{2} - 16})

What is the tangent of f(x)=sin(x)+3,\at x=pi ?
The tangent of f(x)=sin(x)+3,\at x=pi is y=-x+3+pi